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1.4第2课时单项式与单项式相乘1.(-5a2b)·(-3a)等于()A.15a3bB.-15a2bC.-15a3bD.-8a2b2.(2a)3·(-5b2)等于()A.10a3bB.-40a3b2C.-40a3bD.-40a2b3.(2a3b)2·(-5ab2c)等于()A.-20a6b4cB.10a7b4cC.-20a7b4cD.20a7b4c4.(2x3y)2·(5xy2)·x7等于()A.-20x6y4B.10xyy4C.-20x7y4D.20x14y45.下列计算正确的是()A.9a3·2a2=18a5B.2x5·3x4=5x9C.3x3·4x3=12x3D.3y3·5y3=15y96.下列计算错误的是()A.(-2.4x2y3)·(0.5x4)=-1.2x6y3B.(-8a3bc)·=a4b2cxC.(-2an)2·(3a2)3=-54a2n+6D.x2n+2·(-3xn+2)=-3x3n+47.(-x5)2·(-x5·x2)2=.8.(xn)2+5xn-2·xn+2=.9.=.10.(4×103)3·(-0.125×102)2=.11.(0.1ab3)·(0.3a3bc)=.12.a3x3(-2ax2)=.
13.xy·=-xy2z.14.计算.(1)(-3an+2b)3(-4abn+3)2;(2)(-7a2xn)(-3ax2)(-amxn)(m>0,n>0);(3)(-10x2y)·(2xy4z)(4)(-2xy2)·(-3x2y4)·(-xy)
答案:1.A2.B3.C4.D5.A6.C7.x248.6x2n9.4x1410.101311.0.03a4b4c12.-2a3x513.-yz14.解:(1)-432a3n+8b2n+9.(2)-2lam+3x2n+2.(3)-20x3y5z(4)(-2xy2)·(-3x2y4)·(-xy)=-6x1+2+1·y2+4+1=-6x4y7
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